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Singular Integral Operators Child And Euler Equations

Posted on:2007-04-24Degree:DoctorType:Dissertation
Country:ChinaCandidate:X R ZhuFull Text:PDF
GTID:1110360185459964Subject:Basic mathematics
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In chapter 1 we consider the integrality of strong maximal operator on Rn. For a function f∈ Lloc(Rn), its Hardy-Littlewood maximal function is defined bywhere Q is a cube with sides parallel to the coordinate axes, its strong maximal function is defined bywhere P is a rectangle with sides parallel to the coordinate axes. In addition, let M*(f)(x) = Mn 。…。 M1(f)(x) where Mj is the Hardy-Littlewood maximal operator on R1 acting on the j — th coordinate Xj.It is well-known that for f with compact support in [66] Stein proved that: M(f) G ∈L1(E) for any measurable set E of finite measure if and only if f ∈ L ln+ L(Rn).In [38] Jessen-Marcinkiewicz-Zygmund proved that: M*(f) ∈ L1(E) for any measurable set E of finite measure if and only if f ∈ L(ln+ L)n(Rn). This result can also see Fava-Gatto-Gutiérez [31]. Because MS(f) ≤ M*(f), if f G L(ln+L)n(Rn), then MS(f) ∈ L1(E) for any measurable set E of finite measure.It was conjectured in [31] that: if Ms(f) ∈ L1(E) for any measurable set E of finite measure,then f ∈ L(ln+ L)n(Rn). In [1] and [35] Bagby and Gomez independently proved that there are many functions f ∈ L ln+ L(R2) such that Ms(f) ∈ L1(E) for any measurable set E of finite measure.By a different way which can be easily applied to high dimensions case, we shall prove that the conjecture is also not true for n > 2. An interesting thing is that we do not need f ∈ L(ln+L)n-1(Rn). Precisely, we proved...
Keywords/Search Tags:Operators
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