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Weighted Inequalities For Fractional Hardy Operator And Commutators

Posted on:2016-09-08Degree:MasterType:Thesis
Country:ChinaCandidate:D LiuFull Text:PDF
GTID:2180330461477393Subject:Basic mathematics
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In this paper, we study the weighted boundedness of fractional Hardy operator and its related operator.For the maximal operator associated with the fractional Hardy operator, 0 < < 1, we obtain the following results:(1) Let 1 ≤ < 1/, 1/ = 1/- , then is bounded from () to ,∞()if and only if ∈ ,,0.(2) Let 1 < < 1/, 1/ = 1/- , then is bounded from () to () if and only if ∈ ,,0.(3) Let 1 ≤ < 1/, 1/ = 1/- , then is bounded from () to ,∞() if and only if(, ) ∈ ,.(4) Let 1 < < 1/, 1/ = 1/- , then is bounded from () to () if and only if for any > 0,(, ) satisfies(∫ 0[(-′(0,))()]())1/≤ (∫ 0()-′)1/.For two-weight inequalities for the fractional Hardy operator and its dual operator, we obtain the following results:Let 1 < < < ∞, 0 < < 1,(1)(, ) be a pair of weights for which there exists > 1 such that for every > 0,(1/+-1/)(1∫ 0())1/(1∫ 0()-′)1/′≤ ,then(∫ ∞0|)|()1/≤ (∫ ∞0|()|())1/.(2)(, ) be a pair of weights for which there exists > 1 such that for every > 0,(1/+-1/)(1∫ 0())1/(1∫ 0()-′)1/′≤ ,then(∫ ∞0|()|())1/≤ (∫ ∞0|()|())1/.For two-weight inequalities for the commutators of the fractional Hardy operator and the commutators of its dual operator , we obtain the following results:Let 1 < < < ∞, 0 < < 1, ∈ ′max {′,}, and(, ) be a pair of weights for which there exists > 1 such that for every > 0,(1/+-1/)(1∫ 0())1/(1∫ 0()-′)1/′≤ ,then(∫ ∞0|()|())1/≤ (∫ ∞0|()|())1/,and(∫ ∞0|()|())1/≤ (∫ ∞0|)|())1/.
Keywords/Search Tags:Fractional Hardy operator, fractional maximal operator, weight function, two-weight inequality, commutator
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