| In this article, we use[x] for the maximum integer which is no more than the real number x, we use[x] for the minimum integer which is no less than the real number x. We denote by|S| the mumber of the elements in the set.All graphs considered are simple, finite and undirected. For a graph G. we denote the vertex set and the edge set of G by V(G) and E(G). respectively. We use dG(v) for the degree of u in V(G) andâ–³(G) for the maximum degree of G andδ(G) for the minimum degree of G. Let G[V′] denote the induced subgraph of G with vertex set V′and G[E′] denote the induced subgraph of G with edge set E′. We denote by Kn the complete graph on n vertices. We use the symbolsω(G) andκ(G) to denote the number of components of G and the connectivity of G. The independence number of G is denoted byα(G) and the chromatic number of G is denoted byχ(G). For any undefined notation and terminology. we refer the reader to[1].The definition of fractional coloring is given in|6| by E. Scheinerman and D. Ullman. it is fractional generalization of coloring of graphs. Obtain every graph's fractional chromatic number is NP-hard.A mapping C from the collectionζof independent sets of a graph G to the interval[0. 1] is a fractional-coloring if for every vertex x of G. we haveΣ1∈ζ.s.t.x∈I C(I)≥1. The value of a fractional-coloring C isΣ1∈ζ.s.t.x∈I C(I). The fractional chromatic numberλf(G) of G is the infimum of the values of fractionalcoloring of G.Frational-coloring of a graph G has an equivalent definition.λf(G)=(?)λb(G)ï¼b=(?),χb(G) is the b-fold chromatic number of G. Assigns to each vetex of G a set of b colors, and adjacent vertices receive disjoint sets of colors, if all colors are draw from a palette of a colors, We say that G is a: b-colorable. We sometimes refer to such a coloring as an a: b-coloring. The least a for which G has a: b-coloring is the b-fold chromatic number of G.χb(G)=min{a| G has a: b-coloring}.Definition 1 G is fractional colour-critical grpah ifχf(H)<χf(G) for every proper subgraph H of G.Theorem 2. 1. 1 Vertex cut of fractional colour-critical graphs is not clique.Corollary 2. 1. 2 Every fractional colour-critical graph is 2-connected.Theorem 2. 1. 3 suppose G is a graph.v is a vertex of G and X(?)NG(v)is a clique of G contained in the neighbonrhood of v. Let G′be obtained from G by deleting all the edges{vx: x∈X}. thenχf(G′)≥χf(C)-1.Corollary 2. 1. 4 suppose G is a graph. for any edge e of G, thenχf(Gï¼e)≥χf(G)ï¼1.Theorem 2. 1. 5 suppose G is a graph. for any vertex v of G. thenχf(G-v)≥χf(G)-1.Theorem 2. 1. 6 If G is aχf(G)-fractional colour-critical graph, thenδ(G)≥「χf(G)ã€-2.Corollary 2. 1. 7 For every graph G. there are at least「χf(G)ã€-1 vertexs whose degrees are no less than「χf(G)ã€-2.Theorem 2. 1. 8 G. H is Graph with G≠Kn. H≠Kn. n≥1.then G V H is not fractional colour-eritical graph.Theorem 2. 1. 9 If u, v are vertices of G which is fractional colour-critical graph.then N(u)is not subset of N(u). Theorem 2. 1. 10 If G is an n-critical graph andχf(G)=χ(G), for any element t of V(G)∪E(G), thenχf(G-t)=χf(G)-1.Theorem 2. 1. 11 If G is an n-critical graph andχ(G)-χf(G)≤1, then G is fractional colour-critical graph.Theorem 2. 1. 12 G is fractional colour-critical graph andχ(G)=χf(G), Ifχf(G)-χf(G-t)<1, for any element t of V(G)∪E(G), then G is critical graph.Definition 2[8] Suppose G1, G2 are graphs and e=x1y1, e′=x2y2 are edges of G, G′respectively. The Hajos sum of G1 and G2(with respect to e and e′) is the graph obtained from the disjoint union of G1 and G2 by deleting e and e′. identifying x1 and x2, and adding an edge that connects y1 and y2.Theorem 2. 2. 1 Hajos sumG=(G1, x1y1)+(G2, x2y2), then max{χf(G1),χf(G2)}-1≤χf(G)≤max{λf(G1),λf(G2)}.Note: upper bound and lower bound can not improve.Corollary 2. 2. 2 Hajos sumG=(G1, x1y1)+(G2, x2y2), if the graph whose fractional chromatic number is the larger is not fractional colour-critical graph, thenχf(G)=max{χf(G1),λf(G2)}.Theorem 2. 2. 3 Hajos sumG=(Kn, u1u2)+(Km. u1u2), identify u1, u1 into a vertex u0. If m=n. thenχf(G)=n-1/2, otherwiseλf(G)=max{χ(Kn).λ(Km)}-1.Theorem 2. 2. 4 Hajos sumG=(Kn, u1 u2)+(Kn′. u1 u2) is fractional colour-critical graph. where identify u1. u1 into a vertex u0. adding an edge that connets u2 and u2.Definition 3[9] Given 2k+1(k≥1) graphs G0, G1, G2,…, G2k. For i=0, 1, 2,…, 2k. let ei=xiyi be an edge of Gi. Let C2k+1=(c0, c1,…, c2k be a cycle of length 2k+1, Construct a new graph from the disjoint union of G0, G1, G2,…, G2k, C2k+1 as follows: (1): delete the edges ei, for i=0, 1, 2,…, 2k,(2): identify all the xi into a single vertex and name it x,(3): identify yi and ci for i=0, 1, 2,…, 2k.We shall denote the resulting graph by S1(G0, e0, G1, e1, G2, e2,…, G2k, e2k), simply by S1.Theorem 2. 2. 5 Graph S1(G0, e0, G1, e1, G2, e2,…, Gm-1, em-1), simply byS1, ifmax{χf(G0),χf(G1),…,χf(Gm-1)}≥4, thenχf(G)ï¼1≤χf(S1)≤χf(G), whereχf(G)=max{χf(G0),χf(G1),χf(G2),…,χf(Gm-1)}.Note: upper bound and lower bound can not improve.Corollary 2. 2. 6 If the graph whose fractional chromatic number is the the largest is not fractional colour-critical graph. thenχf(S1)=max{χf(Gi).: i=0, 1,…, m-1}.Given m(m≥3) graphs. Gi=Nn, i=1, 2,…, m-1. then S1(G0, e0, G1, e1, G2, e2,…, Gm-1, em-1)=S1(Kn, e0, Kn, e1, Kn, e2,…, Km-1, em-1), simply by S1′.Theorem 2. 2. 7 Graph S1(Kn, e1, Kn, e2, Kn, e3,…, Km, em). simply by S1′. thenχf(S1′)=χf(Kn)-1ï¼Ï‡f(Cm).Given m(m≥3)graphs. Gi is odd cycle Ci for i=0, 1, 2,…, m-1. then S1(G0, e0, G1, e1, G2, e2,…, Gm-1, em-1)=S1(C0, e0. C1, e1, C2, e2,…, Cm-1, em-1), simply by St″.Theorem 2. 2. 8 Graph S1″(C1, e1, C2, e2. C3. e3.…, Cm, em). simply by S1″. thenχf(S1″)=3-1ï¼Ï‡f(Cm).Definition 4[9] Given n graphs G0, G1, G2,…, Gn-1, For i=0, 1, 2,…, n-1. let ei=xiyi be an edge of Gi. Construct a new graph from the disjoint union of G0, G1, G2,…, Gn-1 as follows:(1): delete the edges ei, for i=0, 1, 2,…, n-1.(2): identify yi with xi+1, for i=0, 1, 2,…, n-1.(3): add edges to connect xi and xi+2 for i=0, 1, 2,…, n-1 . (4): add a vertex u and connect u to xi for i=0, 1, 2,…, n-1.We shall denote the resulting graph by S2(G0, e0, G1, e1, G2, e2,…, Gn-1, en-1, simply by S2.Theorem 2. 2. 9 Graph S2(G0, e0, G1, e1, G2, e2,…G2k, e2k), simply byS2. then max{χf(Gi): i=1, 2,…, n-1}-1≤χf(S2)≤max{χf(Gi): i=1, 2,…, n-1}+1.Note: lower bound can not improve.Definition 5[10] Suppose k≥3, G0, G1, G2,…, G4k-1 are graphs and for i=0, 1, 2,…, 4k-1, ei=xiyi is an edge of Gi. Let C2k=(c0, c1,…, C2k-1) be a cycle of length 2k. Construct a new graph from the disjoint union of G0. G1, G2,…, G4k-1 as follows:(1): delete the edges ei from Gi, for i=0, 1, 2,…, 4k-1.(2): identify x0, x1,…, x2k-1 into a single vertex x, and for i=0, 1, 2,…, 2K-1. identify yi with ci.(3): for i=0, 1, 2,…, 4k-1. identify xi with ei-2k and yi with ci-2k+3, where the addition is modulo 2k.We shall denote the resulting graph by S3(G0, e0, G1, e1, G2, e2,…, G4k-1, e4k-1). simply by S3.Theorem 2. 2. 10 Graph S3(G0, e0, G1, e1, G2, e2,…, G4k-1, e4k-1), simple byS3, if max{λf(Gi): i=0, 1, 2.…, 4k-1}≥7, then max{χf(Gi): i=1, 2,…, 4k-1}-1≤χf(S3)≤max{χf(Gi): i=1, 2,…, 4k-1}.Note: upper bound and lower bound can not improve.Corollary 2. 2. 11 If the graph whoso fractional chromatic number is the largest is not fractional colour-critical graph. thenλf(S3)=max{λf(Gi): i=0, 1,…, 4k-1}.Definition 6[9] Given 7 graphs G1. G2.…, G7. Let P5 be the path with five vertices P1, P2,…. P5. For i=1, 2,…, 7. let ei=xiyi be an edge of Gi. Construct a new graph from the disjoint union of G1, G2,…, G7 and P5 as follows:(1): delete the edges ei. for i=1, 2,…, 7, (2): identify y1, y2, y3, y4, y5, into a single vertex, and name it y, and identify xi with pi for i=1, 2,…, 5, and name it xi,(3): identify x6 with x2, y6 with x5, x7 with x1, y7 with x4.We shall denote the resulting graph by S4(G1, e1, G2, e2,…, G7, e7), simply by S4.Theorem 2. 2. 12 Graph S4(G1, e1, G2, e2, G3, e3,…, G7, e7), simply byS4, if max{χf(Gi): i=1, 2,…, 7}≥6, then max{χf(Gi): i=1, 2,…, 7}-1≤χS4≤max{χf(Gi): i=1, 2,…, 7}.Note: upper bound and lower bound can not improve.Corollary 2. 2. 13 If the graph whose fractional chromatic number is the largest is not fractional colour-critical graph, thenχf(S4)=max{χf(Gi): i=1, 2,…, 7}.Definition 7 Distance join graph GVDG′defined as follows: vertex set is V(G)∪V(G′), edge set is E(G)∪E(G′)∪{(i′, j″)|d(i″, j″) = k, k∈D, i″corre-spond with i′∈V(G)}, where G′is the copy of graph G, V(C)= {1′, 2′.…, n′}. V(G′)={1″, 2″,…. n″}, and D=N∪{0}.Lemma 2. 3. 1 Any independent setâ… of distance join graph GVDG′. there is an independent setâ… â€²in G or G′. such that(?)f(i)=(?) f′(i′)(=(?)f′(i″)), where f′is optimal fractional clique of G and G′, the fractional clique f be defined by f′as follows:Theorem 2. 3. 2 Distance join graph GVDG′. D={0. 1}, thenχf(GVDG′)=2λf(G).Theorem 2. 3. 3 If G is fractional colour-critical graph, then GVDG′={0, 1} is fractional colour-critical graph. Theorem 2.3.4 CnVDC′n, D={k} is distance join graph, thenNote: Ifα(G)=2m-k+1, then Xf(CnVDC′n)=(4m+2)ï¼(2m-k+1).Theorem 2.3.5 CnVDC′n,D={0, k} is distance join graph, thenNote: Ifα(G)=m, then Xf(CnVDC′n)=2xf(Cn). Ifα(G)=2m-k+1, then Xf(CnVDC′n)=(4m+2)ï¼(2m-k+1).Theorem 2.3.6 CnVDC′n, D={k, k+1}, k≤m-1 is distance join graph. then Xf(CnVDC′n)≤2Xf(Cn).Note: Ifα(G)=m. then Xf(CnVDC′n)=2Xf(Cn).Theorem 2.3.7 CnVDC′n, D={k, k+2,...,k+i,}is distance join graph, i is even and k+i≤m, thenNote: Ifα(G)=2m-(k+i)-1, then Xf(CnVDC′n)=(4m+2)ï¼(2m-(k+i)-1).Definition 8 Let G be a graph with vertex set and edge set E0. Given an integer m≥1, the m-Mycielskian of G, denoted byμm(G), is the graph with vertex set V0∪V1∪V2∪…∪Vm∪{u}. where is the ith distinct copy of V0 for i=1.2….m.and edge setWe defineμ0(G) to be the graph obtained from G by adding a universal vertex u. The Mycielskian of G. denoted byμ(G), was simplyμ1 (G). is given in [12] by Claude Tardif. in this article, we give another proof about supremum of Xf(μm(G)).Theorem 2.4.1 For any graph G with Xf(G)=a/b and exists a a: b-colouring, then Xf(μm(G))≤aï¼b+bmï¼B′, where B′=bm+bm-1(a-b)…+b(a-b)m-1+(a-b)m, and integers m≥0.Theorem 2.4.2 Graphμm(Kn) with integers m≥1, n≥3 is fractional colour-critical graph.Definition 9 Let G be a graph with one universal vertex, and G′is the copy of G. We define G(?)G′as follows: vertex set is V(G)∪V(G′), edge set is E(G)∪E(G′)∪{u′vi:u′∈V(G′) is universal vertex of G′. vi∈V(G)}∪{uv′i:is universal vertex of G, v′i∈V(G′)}.Theorem 2.4.3 Graph G(?)G′, then Xf(G(?)G′)=Xf(G)+1. |