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Synthesis And Properties Of C2-symmetric Biheterocycle-fused 1,1'-binaphthyl-2,2'-diols

Posted on:2019-03-26Degree:MasterType:Thesis
Country:ChinaCandidate:K AnFull Text:PDF
GTID:2371330566961153Subject:Organic Chemistry
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Heterocycle-fused aromatic compounds based on chiral binaphthol skeleton have been widely used in the field of molecular recognition and asymmetric synthesis.In addition,binaphthols are also widely used in the field of organic optoelectronic materials due to their conjugated structure.In view of the potential applications of heterocyclic fused aromatic compounds in the fields of chiral recognition and asymmetric catalysis,a series of C2-symmetric heterocycle-fused binaphthols were designed and synthesized in this thesis.These noval chiral binaphthols are completed by well-defined synthetic routes by introducing various heterocycles at 5,5',6,6'-positions of binaphthols.Hence,heterocycles such as indole,oxadiazole,thiadiazole,selenadiazole,phenanthridine ring were chosen for this propose.FIrstly,the evaluation of?S?-/?R?-11,11'-diethyl-11H,11'H-4,4'-dibenzo[a]carbazole-3,3'-diols is presented.?S?-/?R?-2,2'-Dihydroxy-7,7',8,8'-tetrahydro-[1,1'-binaphthyl]-5,5'-?6H,6'H?-dione,a key intermediate,is obtained by oxidation of?S?-/?R?-H8-BINOL with DDQ in 1,4-dioxane and water,followed by reaction with CH3I to protect hydroxyl groups.Then Fisher indole syntheses were performed with arylhydrazine hydrochlorides to afford indole-fused compounds,and N-substitutions is finished by the reacting with C2H5Br in the presence of base,followed by dehydrogenation with DDQ to give?S?-/?R?-11,11'-diethyl-3,3'-dimethoxy-11H,11'H-4,4'-bibenzo[a]carbazoles.Demethylation with BBr3 were finalized to give?S?-/?R?-11,11'-diethyl-11H,11'H-4,4'-dibenzo[a]carbazo-le-3,3'-diols.The second part is focused on syntheses of diazole-fused binaphthols,?S?-/?R?-6,6'-dinanaphtho[1,2-c][1,2,5]oxadiazole/thiadiazole/selenadiazole-7,7'-Diphenols.The nitration of?S?-/?R?-BINOL with fuming HNO3 led to 6,6'-dinitro-binaphthol,which reacted with CH3I to form ether,then two amino groups at 5,5'-positions were introduced with tBuOK and 4-amino-1,2,4-triazole as amino source to form the key intermediates?S?-/?R?-2,2'-dimethoxy-6,6'-dinitro[1,1'-binaphthalene]-5,5'-diamine.The oxadiazoles?S?-/?R?-6,6'-dinanaphtho[1,2-c][1,2,5]oxadiazole-7,7'-diols could be obtained by the reaction of this key intermediate with NaClO in EtOH-NaOH to give the nitrogen oxides of oxadiazoles,which deoxidized with NH2OH.HCl/KOH and finally demethylated with BBr3.Asforthiadiazolesandselenadiazoles,?S?-/?R?-2,2'-dimethoxy-6,6'-dinitro-[1,1'-binaphthalene]-5,5'-diamine was reduced with SnCl2/conc.HCl to form?S?-/?R?-2,2'-dimethoxy-[1,1'-binaphthalene]-5,5',6,6'-tetraamine hydrochlorides,which was treated by reaction with SOCl2 or SeO2 respectively to form thiadiazoles or selenadiazoles.The demethylations with aq.HBr or AlCl3 give?S?-/?R?-6,6'-dinaphtho[1,2-c]-[1,2,5]thiadiazole-7,7'-diol/?S?-/?R?-6,6'-dinaphtho-[1,2-c][1,2,5]selenadiazole-7,7'-diol.The third part is to evaluate?S?-/?R?-[9,9'-dibenzo[a]phenanthridine]-10,10'-diols.6,6'-Dinitro-1,1'-binapthano-2,2'-diol,obtained by the nitration of?S?-/?R?-BINOL fuming HNO3,reacted with CH3I to form dimethoxy ethers,which were subsequently reduced with Pd/C-NH2NH2.H2O to give?S?-/?R?-2,2'-dimethoxy-[1,1'-binaphthyl]-6,6'-diamines.Theminations with NBS form?S?-/?R?-2,2'-dimethoxy-5,5'-dibromo-[1,1'-binaphthyl]-6,6'-diamines,which reacted with phenylboronic acid by palladium-catalyzed Suzuki coupling,then acylated with acyl chloride,followed by the ring closure with P2O5/POCl3.Then BBr3 is employed for demethylation to give the target molecules?S?-/?R?-[9,9'-dibenzo-[a]phenanthridine]-10,10'-diols.
Keywords/Search Tags:BINOL, C2-symmetric, Carbazole, Oxadiazole, Thiadiazole, Selenadiazole, Phenanthridine
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