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Strengthening Behavior On The Surface Of Metals By Single Different Abrasives Via Finite Element Simulation

Posted on:2022-08-06Degree:MasterType:Thesis
Country:ChinaCandidate:Y BaiFull Text:PDF
GTID:2481306350493764Subject:Mechanical engineering
Abstract/Summary:PDF Full Text Request
In the process of polishing the metal surface,abrasives can affect its surface quality,but it is difficult to observe the changes of the workpiece in real time during the actual polishing process,and the polishing process can be simplified as abrasive cutting the surface of the workpiece,so simulation methods can be used for analysis.This paper establishes a three-dimensional model of single-grain abrasive cutting workpieces based on ABAQUS.Firstly,it compares and analyzes the effects of diamond,Al2O3 and quasicrystal abrasives on stainless steel,aluminum alloy and copper workpieces.Based on the mathematical relationship between equivalent plastic strain and hardness,the workpiece after cutting is predicted the hardness trend of the subsurface layer of the surface;Secondly,the hardness prediction of the subsurface layer of the workpiece is verified by the experimental data;finally,the influence of different shaped abrasives on the surface stress and strain of stainless steel,and the effect of spherical diamond,Al2O3,quasicrystal,silicon oxide and silicon carbide abrasives on stainless steel are studied.influences.The main research contents and conclusions are as follows:(1)By simulating diamond,Al2O3 and quasicrystal abrasives to cut the surface of 304 stainless steel,it can be seen that the longitudinal gradient equivalent plastic strain values of different positions on the stainless steel surface are quasicrystal>Al2O3>diamond,indicating that the stainless steel cut by quasicrystal abrasives induces Greater plastic deformation.Through the mathematical relationship between equivalent plastic strain and hardness,it is concluded that the greater the plastic strain value of the same workpiece,the greater the hardness.The maximum equivalent plastic strain values of stainless steel cut by quasicrystal,Al2O3 and diamond abrasives are0.73,0.57 and 0.35,respectively.The hardness of stainless steel cut by quasicrystal abrasives is greater than that of the other two traditional abrasives.Therefore,plastic strain can predict the hardness trend of the stainless steel subsurface layer.(2)Cutting the surface of 2024 aluminum alloy and copper by simulating diamond,Al2O3 and quasicrystal abrasives,the maximum equivalent plastic strain values of the aluminum alloy surface cut by abrasives are quasicrystal,diamond,Al2O3 in order from large to small.This trend is consistent with the hardness of aluminum alloys is consistent;the average value of the maximum equivalent plastic strain on the copper surface cut by quasicrystal abrasives is 1.5 times that of Al2O3 and diamond abrasives.The hardness of copper treated with quasicrystal abrasives is greater than that of Al2O3 and diamond abrasives from 300 nm to 1400 nm.The surface of 304 stainless steel,2024 aluminum alloy and red copper after quasicrystal abrasive cutting all induce different degrees of plastic strain,which promotes the increase of the surface hardness of the workpiece.(3)For the quasicrystal single-grain abrasives of spherical,triangular prism,prism and knife shapes for cutting stainless steel,the equivalent stress of the spherical shape is 2.6 times that of the knife shape,and the equivalent strain of the spherical shape is 5 times that of the triangular prism shape,so the spherical abrasive It has the deepest impact on stainless steel longitudinal direction.For spherical diamond,Al2O3,quasicrystal,silicon oxide and silicon carbide abrasives,quasicrystal abrasives have the deepest longitudinal effect on the equivalent stress of 304 stainless steel,and silicon oxide abrasives have the shallowest effect;the maximum average equivalent strain on the surface of the stainless steel treated with abrasives is from large to small,quasicrystal is 0.77,silicon carbide is 0.75,diamond is 0.64,silicon oxide is 0.60,and Al2O3 is 0.47.As the number of cuts increases,the strain accumulates,and the strain of stainless steel after spherical quasicrystal abrasive cutting is the largest.
Keywords/Search Tags:Quasicrystal abrasive, Finite element simulation, Plastic deformation, Work hardening
PDF Full Text Request
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