Phosphates are very important basic materials agricultural and other industrial applications. The removal of Phosphates from surface waters is generally necessary to avoid problems, such as eutrophication. The study is based on the engineering design of a WWTP in Guangdong industrial transfer park, which was found that the Phosphates ofⅡand three-tier effluent didn't meet the standard and the SS of the secondary effluent didn't meet the standard in the operation situation. In the view of this situation, it is chosen that the process should be stable and reliable, management convenient and low cost. And based on result of experiment in the lab, design the flocculation process after biological treatment and strengthen wetland matrix process, and verify the flocculation process after biological treatment by the engineering implementation. Therefore, it is the most important that choose the suitable flocculants and matrix. The conclusion as follows:(1) Based on the phosphorus adsorption isotherm, its kinetics and desorption experiment, the characteristics of phosphorus adsorption, its kinetics and desorption were investigated onto zeolite,quartz sand,shale,anthracite,biological ceramsite and sponge iron; In addition,the ability of the substrate absorption phosphorus is verified again by means of the substrate absorption column. At last, we make ues of the security and economic snalysis to determine that anthracite is the best substitute for traditional substrate.(2) By the experiment, PAC is better than PFS,FeSO4·7H2O and gathering them and PAM, and the cost of PAC is lower. So PAC is selected.(3) The result of engineering implementation shows that the process improves not only the MLSS concentration but also the biological properties, enhances the ability of phosphorous removal and the biological system, reaches the level 1 B standard of《Discharge standard of pollutants for municipal wastewater treatment plant》(GB 18918—2002),and achieves the stable running of WWTP. At last, it is determined that PAC's optimal dosage is 10mg/L. |