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The VUV Luminescence Properties Of M2SiO4:RE (M=Mg, Sr, Ba, RE=Tm~(3+),Tb~(3+))

Posted on:2009-03-17Degree:MasterType:Thesis
Country:ChinaCandidate:P Z LuFull Text:PDF
GTID:2120360242466010Subject:Optical Engineering
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Now, more and more scholars pay their attention to the phosphors used for PDP (plasma display panel). Silicate phosphors are promising as candidates of host materials for the new VUV phosphors with various crystal structures and high chemical stability. In this article, it was attempted to prepare rare ion doped M2SiO4 phosphor by the solid-state reaction and their luminescent properties under VUV were investigated.The X-ray powder diffraction data of M2SiO4: RE (M=Mg, Sr, Ba, RE=Tm3+, Tb3+) is in agreement of JCPDS standard card (87-0061, 39-1256, 26-1403), which indicates that the doped rare ion have little influence on the structure of luminescent host. It indicates that single-phased M2SiO4 phosphor can be obtained in such synthesis process.The VUV excitation spectrum under 457nm of M2SiO4: Tm3+ (M=Mg, Sr, Ba) shows two peaks at about 170nm and 190nm and a broad excitation band from 211nm to 300nm. The former can be assigned to the absorption of the host lattice, which is shifted towards longer wavelengths as the radius of alkali earth ion in M site increases (Mg2+<Sr2+<Ba2+). The latter corresponds to the O-Tm3+ charge transfer transitions, which is weakened as the radius of alkali earth ion in Re site increases. In the VUV emission spectra of M2SiO4: Tm3+ (M=Mg, Sr, Ba) under 161nm excitation, The emission peaks at 357nm, 459nm and 478nm are corresponding to 1D2→3H6, 1D2→3H4 and 1G4→3H6 transitions of Tm3+, respectively.The VUV excitation spectrum of Ba2SiO4: Tb3+ under 545nm consists of two broad bands peaked at 186nm and 238nm, respectively. The former can be assigned to the absorption of the host lattice, and the latter corresponds to the O- Tb3+ charge transfer transitions, in the vuv emission spectrum of Tb3+ under 161nm excitation, the emission peaks at 486 nm, 545 nm, 589 nm and 623 nm corresponds to the 5D4→7Fj(J=6, 5, 4, 3) transitions of Tb3+. The emission spectra of Ba2SiO4: Tb3+ have revealed that an intense and sharp (545 nm) green emission from Tb3+ (5D4—7F5).In the XRD parttens of Ba2-xSrxSiO4: Tb3+ when X=0, the XRD partten of Ba2SiO4: Tb3+ accords with the JCPDS standard card of 26-1403. The diffraction peaks of Ba2SiO4 are weakened as the value of X increases and the diffraction peaks of Sr2SiO4 is stronger as the value of X increases. In the VUV excitation spectrum of Ba2-xSrxSiO4: Tb3+ under 545nm, the absorption intensity of the host lattice, which is about 186nm and 238nm, is weakened as x increases. The absorption peak is shifted towards longer wavelengths. The VUV emission spectrum of Ba2-xSrxSiO4: Tb3+ consists of four peaks at 491nm, 545nm, 589nm, 624nm, respectively. They are duo to the transitions of Tb3+(5D4-7Fj, J=6, 5, 4, 3), and the excitation of 545nm is the strongest. The emission intensity is different of the change of x in the doped same activation ion, but it doesn't show the disciplinarian change as the ratio of Ba/Sr increases. The emission intensity of Ba0.4Sr1.6SiO4: Tb3+ is the strongest.
Keywords/Search Tags:PDP, phosphor, rare earth, silicate
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