The Optimization Of The End Distributione Routing Of Express Delivery Enterprises Based On Crowdsourcing Mode

In recent years,with the rapid development of e-commerce,online shopping is also growing.This phenomenon has increased the business volume of Express enterprises,but also brought difficulties such as end distribution,especially the "last mile" problem to become the key to restricting the development of e-commerce.Therefore,most of the express companies are trying to improve the end distribution efficiency by changing the end distribution mode to reduce the end delivery cost.The express crowdsourcing mode provides a new way to solve the end distribution problem.This paper takes the end distribution route of Express enterprise as the research object,and studies the traditional express end distribution routing problem and the express end distribution routing problem under crowdsourcing mode.The main research contents are as follows:First of all,on the basis of the traditional vehicle routing problem of the end distribution of express,studies the end distribution routing problem of express enterprise based on customer satisfaction,and constructs the model and solves it with genetic algorithm.What's more,take the express crowdsourcing into consideration,studies the end distribution routing problem of Express enterprise based on crowdsourcing mode and customer satisfaction,and constructs mathematical model.According to the need of the problem,genetic algorithm and k-means algorithm are used to solve it.Finally,Through A express company's daily vehicle delivery routing as empirical data,combined with Baidu map,compare the traditional express company's end distribution routing problem based on the customer satisfaction with the express company's end distribution routing problem based on crowdsourcing mode and customer satisfaction,through empirical analysis of the paper to verify the "the express company's end distribution routing problem based on crowdsourcing mode and customer satisfaction" has high application value.